[解析]
解:(1)2A﹣3B
=2(3x2+3y2﹣2xy)﹣3(xy﹣2y2﹣2x2)
=6x2+6y2﹣4xy﹣3xy+6y2+6x2
=12x2+12y2﹣7xy;
(2)由题意可知:2x﹣3=±1,y=±3,
∴x=2或1,y=±3,
由于|x﹣y|=y﹣x,
∴y﹣x≥0,
∴y≥x,
当y=3,x=2时,
原式=12(x2+y2)﹣7xy
=12(x2+2xy+y2﹣2xy)﹣7xy
=12(x+y)2﹣31xy
=12×25﹣31×6
=114,
当y=3,x=1时,
原式=12×16﹣31×3
=99.