[答案]
(1)P∩S={(0,3),(1,1)},Q∩S={(0,3),(1,2)};
(2){(0,3),(1,1),(1,2)}.
[解析]
解:(1)∵S={(x,y)|x∈N,y∈N},P={(x,y)|y=﹣2x+3},Q={(x,y)|y=﹣x2+3}.
∴P∩S={(x,y)|y=﹣2x+3}∩{(x,y)|x∈N,y∈N}={(0,3),(1,1)},
Q∩S={(x,y)|y=﹣x2+3}∩{(x,y)|x∈N,y∈N}={(0,3),(1,2)};
(2)(P∩S)∪(Q∩S)={(0,3),(1,1)}∪{(0,3),(1,2)}={(0,3),(1,1),(1,2)}.
[点评]
本题考查了"交集及其运算,",属于"常考题",熟悉题型是解题的关键。