[答案]
(1)11xy+3y2,2x+5y﹣11xy﹣3y2;
(2)8.
[解析]
解:(1)A=(2x+y)2﹣(x﹣2y)(4x+y)
=4x2+4xy+y2﹣(4x2+xy﹣8xy﹣2y2)
=4x2+4xy+y2﹣(4x2﹣7xy﹣2y2)
=4x2+4xy+y2﹣4x2+7xy+2y2
=11xy+3y2,
B=(2x2y+5xy2)÷xy﹣y(11x+3y)
=2x+5y﹣11xy﹣3y2;
(2)∵A+B=3,
∴11xy+3y2+(2x+5y﹣11xy﹣3y2)=3,
∴2x+5y=3,
∴4x•32y
=(22)x•(25)y
=22x•25y
=22x+5y
=23
=8.
[点评]
本题考查了"整式的混合运算,",属于"基础题",熟悉题型是解题的关键。